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Passions in Poetry

Math Problem Up for Grabs

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Christopher
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Purgatorial Incarceration


0 posted 01-20-2005 12:19 PM       View Profile for Christopher   Email Christopher   Edit/Delete Message      Find Poems  View IP for Christopher


If anyone wants to give it a shot - I've been working on this one for a couple days now and am wholly lost. *shrug*


Here is my known equation as I have it set up right now (this part works):

B = TC (Listed separate from TC because B will be changing in a moment, which is where my problem is)

TC = (SC+STC+C) + ((SC+STC+C) x H%)

Known variables are B, TC, SC, STC, & H%

When TC does not = B, I need to solve for the adjustment of C in order to make TC = B
The part I'm having such difficulty with is that H% is a percentage, which means whenever SC, STC, and/or C changes, the value of ((SC+STC+C) x H%) is adjusted by a different amount every time.
The closest I've been able to come (and I don't even know if I'm even on the right track) is as follows:

((H%/B)*(B-TC)*100)+(B-TC)+C

Honestly, I've tried dozens of approaches & have come close a couple of times, but cannot seem to solve it.
Christopher
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Purgatorial Incarceration


1 posted 01-20-2005 12:32 PM       View Profile for Christopher   Email Christopher   Edit/Delete Message      Find Poems  View IP for Christopher

here's an Excel spreadsheet as an example for the base equation.
http://egowhores.com/temp/Sample.xls
Ron
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2 posted 01-20-2005 07:42 PM       View Profile for Ron   Email Ron   Edit/Delete Message      Find Poems   Click to visit Ron's Home Page   View IP for Ron

The only trick, Chris, is that you first to have rearrange the equation so that you are solving for C.

TC = (SC+STC+C) + ((SC+STC+C) * H)
TC-SC-STC = C + ((SC+STC+C) * H)
(TC-SC-STC)/H = (C/H) + SC + STC+ C
( (TC-SC-STC)/H) - SC - STC = C/H + C
( (TC-SC-STC)/H) - SC - STC = C * (H+1)/H (factoring out H)
( ( (TC-SC-STC)/H) - SC - STC) / ( ( (H +1) /H ) = C

Simplifying the terms, we get:

((TC-SC-STC) - H*(SC+STC)) / (H + 1) = C

If the value of B changes, plug that into the equation to find the new value of C

((B-SC-STC) - H*(SC+STC)) / (H + 1) = C

If that doesn't make sense, Chris, email me and I'll send you a revised spreadsheet.  
serenity blaze
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3 posted 01-20-2005 08:11 PM       View Profile for serenity blaze   Email serenity blaze   Edit/Delete Message      Find Poems  View IP for serenity blaze

*shudder*
Balladeer
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4 posted 01-20-2005 11:15 PM       View Profile for Balladeer   Email Balladeer   Edit/Delete Message      Find Poems   Click to visit Balladeer's Home Page   View IP for Balladeer

Ron took the words right out of my mouth!!
serenity blaze
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5 posted 01-20-2005 11:26 PM       View Profile for serenity blaze   Email serenity blaze   Edit/Delete Message      Find Poems  View IP for serenity blaze

Nod.

Yep.

That woulda been my second guess.

Christopher
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Purgatorial Incarceration


6 posted 01-23-2005 04:06 AM       View Profile for Christopher   Email Christopher   Edit/Delete Message      Find Poems  View IP for Christopher

very, very cool.

it worked no problem, makes my life much eaiser to be sure.

one question (and this may be one of the places where i got myself stuck) - what does adding 1 to H do when factoring it out?

thank you, Ron.

egowhores.com - really love yourself.

Ron
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7 posted 01-23-2005 08:00 PM       View Profile for Ron   Email Ron   Edit/Delete Message      Find Poems   Click to visit Ron's Home Page   View IP for Ron

We had to factor C/H+C, of course, so C could be isolated from H.

C/H + C
C/H + C/1 [this is where the 1 will come from, but we want to multiply instead so ...]
(C * 1/H) + (C* 1/1) [with C on both sides we can now factor C to isolate it]
C * (1/H + 1/1) [which can then be simplified to ... ]
C * (1/H + 1) [could have actually stopped here]
C * (H+1)/H [but tightening the parens seemed a bit cleaner to me]

That final simplification has a name (Law of Unity?), but really is just the way Unity always works ...

1/2 + 1/1 = (2+1)/2 = 3/2
1/3 + 1/1 = (3+1)/3 = 4/3
1/4 + 1/1 = (4+1)/4 = 5/4


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